
Re: [中學] 高中一題數列與級數問題

[(a_n + 2)/2]^2 = 2S_n
8S_n = (a_n + 2)^2
8a_1 = (a_1 + 2)^2 => a_1 = 2
8a_n = (a_n + 2)^2 - [a_(n-1) + 2]^2
=> (a_n - 2)^2 = [a_(n-1) + 2]^2
由題設知
=> a_n = a_(n-1) + 4
=> a_2015 = 2 + 4 * 2014 = 8058
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