Re: [線代] 幾題線代

看板Math作者 (Farewell)時間6年前 (2018/07/07 12:06), 編輯推噓0(000)
留言0則, 0人參與, 最新討論串3/3 (看更多)
※ 引述《Aquarkbrain (腦容量只有夸克)》之銘言 : Let R^n be regarded as column vectors. : 2. Let X be the linear subspace of R^2*3 containing all matrices whose co lumns : add to 0 ∈ R^2. Similarly let Y be the subspace of R^2*3 containing all ma : trices whose rows add to 0 ∈R^3. : (a) What is the dimension of X. : (b) What is the dimension of (X+Y). (a) A in X, A = [ a b c ] [ d e f ] then X = { A in X | a+b+c = 0, d+e+f = 0 } Let T: R^2*3 -> R^2, T(A) = (a+b+c, d+e+f) then T is surjective and kerT = X by dimension theorem dimX = 4 similarly dimY = 3 (b) consider A in X cap Y take a, b arbitrary we have A = [ a b -a-b ] [ -a -b a+b ] Now dim(X+Y) = dimX + dimY - dim(X cap Y) = 4 + 3 - 2 = 5 we can also observe that [ 0 0 -1 ] [ 0 0 1 ] in Y but not in X, and [ 0 0 0 ] [ 0 0 1 ] not in X+Y thus dimX < dim(X+Y) < dimR^2*3 but the latter one is not easy to prove though ---- Sent from BePTT -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 49.214.225.10 ※ 文章網址: https://www.ptt.cc/bbs/Math/M.1530936370.A.478.html
文章代碼(AID): #1RG3moHu (Math)
文章代碼(AID): #1RG3moHu (Math)