Re: [中學] 幾何
→ → →
AD = (1/2)AB + (1/2)AC
→ → →
AG = tAB + (1-t)AE
→ → → → →
= tAB + (1-t)(1/3)AC // AD // AB + AC
t (1-t)(1/3)
=> --- = ----------
1 1
=> t = 1/4
→ → →
=> AG = (1/4)AB + (1/4)AC
→ → →
同理 AH = (2/5)AB + (2/5)AC
AG 5
---- = ---
AH 8
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標題 [笑話] 機會就像老二 看板 joke
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