Re: [微積] 瑕積分一題

看板Math作者 (喬祺對我如此狠)時間8年前 (2017/05/24 09:37), 編輯推噓0(000)
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※ 引述《petodog (作夢高手)》之銘言: : Suppose that a bank teller takes an exponentially distributed length of time : with mean μ=2 minutes to serve each customer. If there is already one : customer waiting in line, what is the probability that you will wait for more : than 6 minutes? : 不懂要怎麼列式 : 知道用exponential列,但怎麼跟機率扯上關係? probability density = f(t) = Aexp(-t/2) ∞ 1 = ∫f(t)dt = A2 => A = 1/2 0 假如前面一個人剛好這時被服務 則你要等超過6分鐘的機率 ∞ = ∫f(t)dt = exp(-3) 6 -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 61.56.10.112 ※ 文章網址: https://www.ptt.cc/bbs/Math/M.1495589846.A.331.html
文章代碼(AID): #1P9EFMCn (Math)
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文章代碼(AID): #1P9EFMCn (Math)