[機統] 基本機率事件-台大電子所消失

看板Math作者時間9年前 (2016/12/27 10:03), 編輯推噓0(003)
留言3則, 2人參與, 最新討論串1/2 (看更多)
In a contest , contestants A , B and C are asked , in turn , a question. If a contestant gives a wrong answer to the question , he or she will be dropped out of the game. the remaining two will continue to compete until one of them drops out. The last person remaining is the winner. Suppose that a contestant knows the answer to a question independently of the other contestants , with probability P. Let ABC represent the event that A drops first , B next , and C wins . Calculate the probability of P{ABC) 解答 : (1-P)^2 + P^3(1-P)^2+P^6(1-P)^2+...... +(1-P)^2*P^2+P^3(1-P)^2*P^2+P^6(1-P)^2*P^2+..... +(1-P)^2*P^4+P^3(1-P^2)*P^4+P^6(1-P^2)*P^4+..... ~ = (1-P)^2/(1-P^2)*(1/1-P^3) 想請問一下列式成上面是如何列的,謝謝!! -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 163.20.243.69 ※ 文章網址: https://www.ptt.cc/bbs/Math/M.1482804181.A.7E0.html

12/27 10:24, , 1F
第一列是AB同一輪被淘汰 第二列是AB差一輪被淘汰
12/27 10:24, 1F

12/27 10:24, , 2F
以此類推
12/27 10:24, 2F

12/27 10:48, , 3F
第三列是?
12/27 10:48, 3F
文章代碼(AID): #1OOSlLVW (Math)
文章代碼(AID): #1OOSlLVW (Math)