
Re: [中學] 三角形相似,求面積

: 試過多個方法,
: 仍舊求不出,
: 求大家幫忙,
: 謝謝!
AB = x
AC = y
x^2 : y^2 = 9 : 4
x = 3k
y = 2k
=> x + y = 15√13 = 5k
=> k = 3√13
=> x = 9√13, y = 6√13
=> BC = 39
=> CD = (4 / 13) * 39 = 12
=> △ADC = (1/2) * 54 * 13 * [2 / √13 ]^2
= 108
選(B)
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