Re: [分析] limit point有含lim sup嗎

看板Math作者 (QQ)時間12年前 (2013/10/06 23:11), 編輯推噓1(103)
留言4則, 1人參與, 最新討論串2/2 (看更多)
※ 引述《ntme (one shot one kill)》之銘言: : close 裡有所有的limit point : 那lim sup /lim inf也在close裡嗎? 把數列看成集合時,因為集合對於相同的點是一樣的,所以要定義清楚 這問題可以整理成: Let a:N → M be a sequence where N is the set of natural number, M is a metric space Define S = {a(n):n€N} C = all cluster points of the sequence = {p€M:∃subsequence of a_n converging to p} L(S) = {q€M:∀ε>0, ∃x€S, x≠q s.t. d(x,q)<ε} cl(S) = S∪L(S) Then we have: 1. C⊆cl(S) 2. L(S)⊆C 3. from 1.2. we have C∪S = cl(S) ------------------------------------ 而今天你的case是M=R, 可以定義limsup , liminf 加上下面這個定理: <Theorem> a:N → R be a sequence if a(n) is bounded then (i) limsup, liminf are finite (ii) limsup, liminf€C (也就是版友說的,找的到子列去趨近) 所以你問題的答案就是:limsup, liminf€C⊆cl(S) -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 1.171.15.202

10/06 23:29, , 1F
感謝,我想說closed in R1是measurable,所以存在open
10/06 23:29, 1F

10/06 23:31, , 2F
G,s.t. G跟closed 區間任意靠近,所以想說會不會在
10/06 23:31, 2F

10/06 23:32, , 3F
G\closed 裡面
10/06 23:32, 3F

10/06 23:34, , 4F
但看到這篇定義就懂了
10/06 23:34, 4F
文章代碼(AID): #1IKNsKNy (Math)
文章代碼(AID): #1IKNsKNy (Math)