Re: [微積] 兩曲線公切線
※ 引述《stranger522 (香菇勇)》之銘言:
: y=x^2
: y=-x^2+10x-17
: 求兩曲線的公切線
: 不知怎麼下手..有請各位高手~
y = x^2
y = -(x-5)^2+8
公切線:(y-4) = m(x-5/2) => y = mx - 5m/2 + 4 與 y = x^2 交於一點
=> x^2 = mx - 5m/2 + 4 => x^2 - mx + (5m/2 - 4) = 0 唯一解
=> D = (-m)^2 - 4 * 1 * (5m/2 - 4) = 0
=> D = m^2 - 10m + 16 = (m - 2)(m - 8) = 0
=> m = 2 or 8
=> 公切線:y = 2x-1 or y = 8x-16
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 111.252.216.188
推
12/28 23:42, , 1F
12/28 23:42, 1F
→
12/28 23:44, , 2F
12/28 23:44, 2F
推
12/28 23:54, , 3F
12/28 23:54, 3F
→
12/29 00:38, , 4F
12/29 00:38, 4F
→
12/29 00:39, , 5F
12/29 00:39, 5F
討論串 (同標題文章)