Re: [代數] ringR的left ideal只有(0)跟R

看板Math作者 (r=e^theta)時間11年前 (2012/11/09 19:43), 編輯推噓6(600)
留言6則, 4人參與, 最新討論串2/2 (看更多)
※ 引述《ma4wanderer (台師怪客)》之銘言: : 這題是說ring R 的left ideal 只有R跟(0) : 則 : 1.R 是division ring : 或 : 2.has p elements(p is a prime) and ab=0 for all a、b in R : 有個人跟我講考慮這個ideal {r in R| rR=0} : 可是除環的1不知怎麼弄出來 : 還有prime elements哪裡來 : @@ : 有請指點! 1. Ra is a left ideal = R or 0 2. {a| Ra=0} is a left ideal = R or 0 If R, then xy=0 for all x,y. left ideal = (normal) additive subgroup. => cyclic group of order p. If 0, then Ra=R for all a=/=0 3.For a=/=0 {r|ra=0} is a left ideal = R or 0 If R, then Ra = 0, impossible So ra=0 => r=0 conclusion: xy=0 => x=0 or y=0, left and right cancellations. 4. For a=/=0, Ra=R, so there exists e_a, e_a a=a For any b, b e_a a = ba, so b e_a = b by cancellation. Now pick a, b, c=/=0, then b e_a = b = be_c, so e_a = e_c by cancellation. Denote the common element e_a by e, the left and right identity. 5. For a=/=0, Ra=R, so there exists a', a'a=e Then a'aa' =ea' = a'e so aa'=e by cancellation. And a' is the multiplicative inverse of a. -- r=e^theta 即使有改變,我始終如一。 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 219.84.3.42

11/09 20:17, , 1F
讓我膜拜一下
11/09 20:17, 1F

11/09 20:18, , 2F
膜拜一下
11/09 20:18, 2F

11/09 20:29, , 3F
"cyclic" group of order "p" 這邊看無QQ
11/09 20:29, 3F

11/09 21:47, , 4F
Sylow's first theorem
11/09 21:47, 4F

11/09 22:23, , 5F
我好像catch到了
11/09 22:23, 5F

11/10 02:10, , 6F
太神奇了QQ
11/10 02:10, 6F
文章代碼(AID): #1GdEnXER (Math)
文章代碼(AID): #1GdEnXER (Math)