Re: [中學] log的問題....
※ 引述《strekm (strekm)》之銘言:
: Log9p=log12q=log16(p+q)
: P/q=?
: 感恩
log p log q log (p+q)
------ = ------------- = -----------
2log3 2log2 + log3 4log2
=> log (p+q) + log p = 2log q
2 2
p + pq = q
2
(p/q) + (p/q) -1 = 0
-1 ±√5
p/q = ---------- (負不合)
2
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