Re: [其他] 用structural induction 證明

看板Math作者 (scrya)時間14年前 (2011/12/13 01:54), 編輯推噓1(100)
留言1則, 1人參與, 最新討論串2/2 (看更多)
※ 引述《a606155123 (冷氣團團長)》之銘言: : 各位大大有2題要請教 : 用structural induction方法來證 : 1.E=V-1(邊=點-1 跟tree的生成有關) : 2.E=V+F-1 (邊=點+面-1) : 謝謝大大回答!!_ 先回答第一題好了: Basis Step: If there is only one node in the tree, E = 0, V = 1. => E = V - 1 (G1) If there are two nodes, E = 1, V = 2. => E = V - 1 (G2) If there are three nodes, E = 2, V = 3. => E = V - 1 (G3) The following are the graphs above. -------------------------------------------- | | | | | | | | | | | ● | | | | \ | | | | ● | | ● | ●----● | / | | | | ● | | | | | | (G1) | (G2) | (G3) | |------------|---------------|-------------| Suppose the statement is true for all tree with less and equal to n nodes, n > 0. Then, for a tree T = G(V,E) with n+1 nodes, we can divide these tree into two trees by removing an edge connecting two nodes x and y. Let these two trees be T1 = G(V1,E1) containing x and T2 = G(V2,E2) containing y. Then V1 + V2 = V = n+1 and E = E1 + E2 + 1 By our construction, 1 ≦ V1 ≦ n, 1 ≦ V2 ≦ n. Furthemore, by hypothesis, E1 = V1 - 1 and E2 = V2 - 1. Therefore, E = E1 + E2 + 1 = (V1 - 1) + (V2 - 1) + 1 = V1 + V2 -1 = V - 1 = n The statement is true. By structural induction, we complete the proof. -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 111.251.160.15

12/13 13:17, , 1F
感恩感恩!!
12/13 13:17, 1F
文章代碼(AID): #1EvZ_ZgX (Math)
文章代碼(AID): #1EvZ_ZgX (Math)