Re: [中學]
※ 引述《AAJJBurnett (叫我投手)》之銘言:
1 1 1
設非零實數x,y,z滿足 x+y+z= --- + --- + --- =1
x y z
試證: x,y,z中至少有一個為1
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分享個要用到非零條件的解法:p
(x-1)(y-1)(z-1)
=[xyz-(xy+yz+zx)]+[(x+y+z)-1]
=[xyz(1-1/x-1/y-1/z)]+[0]
=xyz*0+0=0
故至少有一個為1
皆不為零才敢大膽地提出來XD
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