Re: [微積] 一題重積分
※ 引述《kurt310452 (憨 人)》之銘言：
: 1 x
: ∫∫ (x-1)*[(x+y)^(0.5)]dydx
: 0 0
1
=∫ (x-1) 2/3(x+y)^(1.5)|y={0~x} dx
0
1
=∫ (x-1) 2(2^(1.5)-1)/3 x^(1.5) dx
0
1
= 2(2^(1.5)-1)/3 ∫ (x^(2.5) - x^(1.5)) dx
0
= 2(2^(1.5)-1)/3 (2/7- 2/5)
= -8(2^(1.5)-1)/105
--
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 163.22.18.20
推
09/09 19:50, , 1F
09/09 19:50, 1F
討論串 (同標題文章)