Re: [微積] 三變數的隱函數微分

看板Math作者 (QQ)時間13年前 (2011/05/12 22:40), 編輯推噓3(303)
留言6則, 2人參與, 最新討論串2/2 (看更多)
※ 引述《sosick (錢錢)》之銘言: : If the equation sin(x+y)+sin(y+z)=1 defines z implicitly : as a differentiable function of x and y , evaluate (Ø^2 z÷ØyØx) : Ø=partial的符號 : 拜託了 卡好久!! sin(x+y) + sin(y+z)=1 (d是partial的符號) partial derivative for x: (A) cos(x+y) + (cos(y+z))*(dz/dx) = 0 → 解得 dz/dx partial derivative for y: (B) cos(x+y) + (cos(y+z))*(dz/dy) = 0 → 解得 dz/dy 由 (A) 再去對y做partial derivative 或是 由 (B) 再去對x做partial derivative 如果從 (A) 對y做的話 (-sin(x+y)) + (-sin(y+z))*(dz/dy)*(dz/dx) + (cos(y+z))*(d^2 z/dydx) = 0 這樣就OK了 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 114.25.176.22

05/12 23:26, , 1F
你到我那篇看一下答案!好像不太依樣...
05/12 23:26, 1F

05/12 23:31, , 2F
........我算了一樣阿= =
05/12 23:31, 2F

05/12 23:34, , 3F
是喔!!可是我算出來分母都是cos^2而已@@
05/12 23:34, 3F

05/12 23:34, , 4F
先生你忘了(cos(y+z))*(d^2 z/dydx) 前面還有一個^^
05/12 23:34, 4F

05/12 23:35, , 5F
我在算依次== "
05/12 23:35, 5F

05/12 23:40, , 6F
OK 會了!!感謝 知道錯在哪兒了~
05/12 23:40, 6F
文章代碼(AID): #1Do_5BC1 (Math)
文章代碼(AID): #1Do_5BC1 (Math)