[微積] 羅必達法則

看板Math作者 (浪子回頭)時間13年前 (2011/03/12 10:59), 編輯推噓0(0推 0噓 7→)
留言7則, 3人參與, 最新討論串1/2 (看更多)
請問各位大大一題有關羅必達法則的運用.. lim t→0 (5^t - 3^t) / t = ? 要怎嚜算????? 謝謝囉!!!!!!!!!!! 感恩~~~~ -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 120.105.159.89
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03/12 11:08, , 1F
上面微分下面微分 (對 t 微分)
03/12 11:08, 1F
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03/12 11:22, , 2F
(5^t ln5 - 3^t ln3)/1 t→0 =ln5-ln3 =ln(5/3)
03/12 11:22, 2F
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03/12 11:24, , 3F
怎嚜讓它變成5^tln5 的?
03/12 11:24, 3F
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03/12 11:34, , 4F
(5^t)' =5^t ln5
03/12 11:34, 4F
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03/12 11:37, , 5F
y=5^t , lny =t*ln5兩邊對t微分 (1/y)y' =ln5 ==>
03/12 11:37, 5F
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03/12 11:37, , 6F
y' =ln5 *y =ln5 *5^t
03/12 11:37, 6F
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03/12 13:28, , 7F
謝謝囉!!!! 推感謝!!!
03/12 13:28, 7F
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文章代碼(AID): #1DUk6LrU (Math)
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文章代碼(AID): #1DUk6LrU (Math)