[微積] 微分
arcsec{(x^2-1)/(x^2+1)} 的微分
想法
當我微到 1/[{(x^2-1)/(x^2+1)}*{{(x^2-1)/(x^2-1)}^2-1}^(1/2)]*{(x^2-1)/(x^2+1)}'
發現根號裡頭的東西剩下-4x^2 如果我沒有微錯 是否代表這個函數不可以微分?
煩請高手解惑 感激不盡
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