[理工] [工數] 矩陣
Write the general solutions to
AX=[1 2 2][X1]=[1]
[2 4 5][X2] [4]
[X3]
as the sum of a particular solution to AX=b
and the general solution to AX=0
請問是要分成AX=b 和 AX=0 求出 Xp 和 Xh再相加嗎?
AX=[1 2 2][X1]=[0] ===> [1 2 2 0] ====>X3=0 >>>[X1]=[-2*X2]=Xh
[2 4 5][X2] [0] [0 0 1 0] X1=-2*X2 [X2] [ X2]
[X3] [X3] [ 0]
AX=[1 2 2][X1]=[1] ===> [1 2 2 1] ====>X3=2 >>> [-2*X2 -3]=Xp
[2 4 5][X2] [4] [0 0 1 2] X1=-2*X2 -3 [ X2 ]
[X3] [ 2]
嗯... 以上是我自己亂解的東西... 由於礙於沒有解答
而且我解的東東看起來一點都沒有正確答案的感覺 @////@"
因此上來求助 感謝解答~~~
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