[理工] [機率] 排列組合

看板Grad-ProbAsk作者 (賴伯)時間14年前 (2011/09/27 22:49), 編輯推噓2(2010)
留言12則, 3人參與, 最新討論串7/8 (看更多)
there are three types of animals in a laboratory:15 type I 13 type II &12 type III.Animals of type I react to a particlar stimulus in 5 sec ,type II and type III react to the same stimulue in 4.5 sec and 6.2 sec, respectively.A psychologist selects 10 of these animals at random and finds the a exactly four of them react to this stimulus in 6.2 sec.What is the prob that at least two of them react to the same stimulus in 4.5 sec. 我的想法是 B = 至少兩隻type II A = 十隻有四隻type III _ P(B│A) = 1 - P(B│A) 12 13 15 12 15 P C C + P C 4 1 5 4 6 =1 - ──────── * 6! (請問這樣列有錯嗎?) 40 P 10 Ans: 0.8831(我跟算的跟答案不一樣 我不知道是我哪列錯 還是計算機按錯?) =========================================================================== 12 13 15 12 15 C C C + C C 4 1 5 4 6 =1 - ───────── 不考慮順序的話 改成這樣 也跟答案不同 40 為什麼?? C 10 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 220.129.38.177

09/27 23:00, , 1F
答案是哪個@@
09/27 23:00, 1F

09/27 23:08, , 2F
0.8831
09/27 23:08, 2F
※ 編輯: lai90043 來自: 220.129.38.177 (09/27 23:10)

09/28 00:18, , 3F
1 - (15C6+15C5*13C1)/(28C6)
09/28 00:18, 3F

09/28 00:19, , 4F
我算也是 0.8831 @@
09/28 00:19, 4F

09/28 01:41, , 5F
P(至少兩隻TYPEII|有四隻TYPEIII)=
09/28 01:41, 5F

09/28 01:42, , 6F
P(至少兩隻TYPEII|六隻TYPEI or TYPEII)=
09/28 01:42, 6F

09/28 01:44, , 7F
1-(13C1*15C5+13C0*15C6)/28C6=0.8831
09/28 01:44, 7F

09/28 01:45, , 8F
這題沒有順序 所以都用組合數就可以了
09/28 01:45, 8F

09/28 08:45, , 9F
樓上那是課本的解法吧 我想問的是 我列式錯在哪裡了?
09/28 08:45, 9F
※ 編輯: lai90043 來自: 220.129.35.110 (09/28 09:26)

09/28 11:29, , 10F
條件機率樣本空間會改變 妳那樣列的意思是從10挑出
09/28 11:29, 10F

09/28 11:32, , 11F
與題目意思不同
09/28 11:32, 11F

09/30 23:27, , 12F
想通了 謝謝
09/30 23:27, 12F
文章代碼(AID): #1EWUA4PE (Grad-ProbAsk)
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文章代碼(AID): #1EWUA4PE (Grad-ProbAsk)