[理工] 拉氏解微方
Solve xy"+2y'+xy = 0
做法:
L[xy"] + 2L[Y'] + L[xy] = 0
-d/ds(s^2Y-cs) + 2(sY-c) + -d/ds(Y) = 0 (let y(0) = c)
整理得
(s^2+1)d/ds(Y) = -c
dY = -c(s^2+1)ds
Y = k1*tan-1(x) + k2
y = k1*1/x(sinx) + k2
但是解答是
k1*1/x(sinx) + k2*1/x(cosx)
請教大家過程哪裡出錯了
麻煩各位!
Thanks
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 220.141.15.218
推
09/26 10:09, , 1F
09/26 10:09, 1F
→
09/26 10:09, , 2F
09/26 10:09, 2F
→
09/26 10:56, , 3F
09/26 10:56, 3F
→
09/26 11:14, , 4F
09/26 11:14, 4F
→
09/26 22:27, , 5F
09/26 22:27, 5F
推
09/27 00:33, , 6F
09/27 00:33, 6F
→
09/27 00:34, , 7F
09/27 00:34, 7F
推
09/27 00:35, , 8F
09/27 00:35, 8F
推
09/27 01:05, , 9F
09/27 01:05, 9F
推
09/27 01:24, , 10F
09/27 01:24, 10F
→
09/27 01:26, , 11F
09/27 01:26, 11F
→
09/27 01:33, , 12F
09/27 01:33, 12F
推
09/27 01:50, , 13F
09/27 01:50, 13F
→
09/11 14:31, , 14F
09/11 14:31, 14F
討論串 (同標題文章)