[商管] [統計]-機率

看板Grad-ProbAsk作者 (小刀)時間13年前 (2010/10/27 09:40), 編輯推噓2(200)
留言2則, 1人參與, 最新討論串7/8 (看更多)
Suppose that the probability of a student knows the correct answer of question #2 is q. What is the conditional probability that a student does not know the answer to question #2 given that he answers it correctly? Assume that student will randomly choose answers if he or she does not know the correct answer. (#2為五個選項的複選題) 我的問題是 解答寫P(對|不知)=1/32,但我不知道這個機率是怎麼算出來的... 請高手指教 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 118.169.167.215

10/27 17:19, , 1F
呃 是P(對|不知)還是P(不知|對) @@
10/27 17:19, 1F

10/27 17:22, , 2F
P(對|不知)=P(對且不知)/P(不知)=(1-q)[(1/2)^5]/(1-q)
10/27 17:22, 2F
文章代碼(AID): #1CnuBuSk (Grad-ProbAsk)
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文章代碼(AID): #1CnuBuSk (Grad-ProbAsk)