
Re: [理工] [機率]-期望值

: 題目意思看得明白
: 但解答第二行開始就看不懂了
: 為何Nk=P(Nk+1)+(1-P)(Nk-1+1+Nk)?
negative binomial...忘了
X1 表第一種情形
1.第一次 tail P(X1 = T) = 1/2
2.第一次為 head P(X1 = H) = 1/2
E(X) = E(X|X1 = T)*P(X1 = T ) + E(X|X1 = H )*P(X1 = H)
= E(X|X1 = T)*(1/2) + (1+E(X))* (1/2)
同理
E(X|X1 = T) 也可以如 E(X) 去計算 再代回去
1.第二次 tail P(X2 = T) = 1/2
2.第二次為 head P(X2 = H) = 1/2
E(X|X1 = T) = E(X|X1 = T,X2=T)*P(X2 = T ) + E(X|X1 = T,X2=F )*P(X2 = F)
= E(X|X1 = T,X2=T)*(1/2) + (2+E(X))* (1/2)
= 2 * (1/2) + ( 2+E(x) )*(1/2)
E(x)= [ 2 * (1/2) + ( 2+E(x))*(1/2) ]*(1/2) + (1+E(x))*(1/2)
=> E(x) = 6
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