[理工] [線代]-求相似矩陣的基底
求M使的B=M^(-1)AM成立
A=
[1 1]
[1 1 ]
B=
[1 -1]
[-1 1]
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◆ From: 124.218.65.42
→
06/15 17:25, , 1F
06/15 17:25, 1F
推
06/15 17:26, , 2F
06/15 17:26, 2F
→
06/15 17:27, , 3F
06/15 17:27, 3F
→
06/15 17:27, , 4F
06/15 17:27, 4F
推
06/15 17:30, , 5F
06/15 17:30, 5F
→
06/15 17:30, , 6F
06/15 17:30, 6F
→
06/15 22:43, , 7F
06/15 22:43, 7F
推
06/16 00:41, , 8F
06/16 00:41, 8F
M=
[1 -1]
[1 1]
AM=
[1 1][1 -1]
[1 1][1 1]=
[2 0]
[2 0]
M^(-1)=
[1/2 1/2]
[-1/2 1/2]
M^(-1)AM=
[1/2 1/2][2 0]
[-1/2 1/2][2 0]=
[2 0] [1 -1]
[0 0]=[-1 1]=B
有問題在這邊
[2 0] [1 -1]
[0 0]=[-1 1]這個等式要怎麼成立?要用到什麼定理
元素相對應可得
2=1
0=-1
0=-1
0=1
※ 編輯: Bruge1986 來自: 124.218.65.42 (06/16 01:21)
推
06/16 04:11, , 9F
06/16 04:11, 9F
→
06/16 04:11, , 10F
06/16 04:11, 10F
M=
[1 1]
[-1 1]
AM=
[1 1][1 1]
[1 1][-1 1]=
[0 2]
[0 2]
M^(-1)=
[1/2 -1/2]
[1/2 1/2]
M^(-1)AM=
[1/2 -1/2][0 2]
[1/2 1/2][0 2]=
[0 0] [1 -1]
[0 2]=[-1 1]=B
有問題在這邊
[0 0] [1 -1]
[0 2]=[-1 1]這個等式要怎麼成立?要用到什麼定理
元素相對應可得
2=1
0=-1
0=-1
0=1
※ 編輯: Bruge1986 來自: 124.218.65.42 (06/16 09:11)
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