Re: [理工] [工數]- ODE
※ 引述《wellilin (QQ12)》之銘言:
: (2x^3y^2-3x^2y)dy+(3x^2y^3-6xy^2+5y)dx=0
: ans: (x^2y^2-3xy+5)x=c
: 喻超凡課本習題.
3 2 2 2 3 2
(2x y - 3x y)dy + (3x y - 6xy + 5y)dx = 0
2 2
x y (2xdy + 3ydx) - 3xy(xdy + 2ydx) + 5ydx = 0
2 2 3 2 2
x y d(x y) 3xyd(x y)
------------ - ----------- + 5ydx = 0
2 x
x y
3 2 2
d(x y) - 3d(x y) + 5dx = 0
3 2 2
x y - 3x y + 5x = c
註:
m n m-1 n m n-1
d(x y) = mx y dx+ nx y dy
m-1 n-1
= x y (mydx + nxdy)
m n
d(x y)
mydx + nxdy = --------------
m-1 n-1
x y
--
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