[理工] [計組]-memory
想請問下面這題 :
Consider a logical-address of 2048 words each,mapped onto a physical
memory of 64 frames. Please answer the following questions assuming
that the smallest memory allocation unit is one byte
(c)Assuning a 2-level page table is used and the first-level table
has 32 entries, what is the minimal amount of memory (in bytes)
required by the page tables?
手邊的答案為 :
level-1 : 2^5*(3+6(for L2))= 32*9 bit= 36 bytes
level-2 : 2^6*(3+6(for physical address))
= 64*9 bit= 72 bytes
total= 36 bytes + 72 bytes = 108 bytes
想請問它這樣解對嗎?? 對這種題目好頭痛orz
麻煩高手解答一下 感謝!!
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