[理工] [工數]-拉式轉換
L{(cos t)u(t-π/2)}=L{-(sin(t-π/2)u(t-π/2)}
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為什麼第二步不是 L{cos(t-π/2)u(t-π/2)}
除了尤拉判斷以外.他的判斷依據又可以是什麼?!
如果變成L{(cos t)u(t-3π/2)}=L{(_____(t-3π/2))u(t-3π/2)}
或者L{(sin t)u(t-π/2)}=L{(_____(t-π/2))u(t-π/2)}
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01/24 14:44, , 1F
01/24 14:44, 1F
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