Re: [理工] [工數]-中正93-光電
※ 引述《aeronautical (退伍後考研所真難熬)》之銘言:
: 此題為93年中正光電http://ppt.cc/Fd7Q
: 第6題向量
: 如要用Green's 定理和路徑參數來解要怎算呀?
: 小弟我一直try不出來..麻煩各位高手了
σ σ
green定理∫∫ ──(cosx) - ── (y-sinx) dxdy
σx σy
=∫∫-sinx - 1 dxdy
π/2 (2/π)x
= ∫ ∫ -(sinx + 1 ) dydx
0 0
π/2 2x
= ∫ - ──(sinx + 1 )
0 π
2 π
= - ── - ──
π 4
--
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