[理工] [工數]-高階ode..
1.
2
(x+1) y'' - 3(x+1)y' + 2y = 0 , y(0) = 0 y'(1) = 2
2+根號2 2-根號2
答案 y = c[(x+1) - (x+1) ]
我是想問 這題怎麼 沒有 c1 c2..
因為我是算成
2+根號2 2-根號2
y = c1(x+1) -c2(x+1)
然後再代初始值
不過 y' 就卡住了 哈..
2.
1 x
y'' - ---y' = (3+x)xe
x
2 t
乘 x 方後 x = e , t = lnx
答案是
2 2 x
y = c1x + c2 + x e
我是算成
2 3 x 1 4 x
y = c1x + c2 + x e + ---x e
8
我只是來確認答案的XD
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 114.32.91.86
→
12/18 13:13, , 1F
12/18 13:13, 1F
→
12/18 13:14, , 2F
12/18 13:14, 2F
→
12/18 13:14, , 3F
12/18 13:14, 3F
推
12/18 14:26, , 4F
12/18 14:26, 4F
推
12/18 16:49, , 5F
12/18 16:49, 5F
→
12/18 16:49, , 6F
12/18 16:49, 6F
推
12/18 17:06, , 7F
12/18 17:06, 7F
推
12/18 17:07, , 8F
12/18 17:07, 8F
推
12/18 17:09, , 9F
12/18 17:09, 9F
推
12/18 17:10, , 10F
12/18 17:10, 10F
→
12/18 17:10, , 11F
12/18 17:10, 11F
推
12/18 17:12, , 12F
12/18 17:12, 12F
→
12/18 17:31, , 13F
12/18 17:31, 13F
→
12/18 17:32, , 14F
12/18 17:32, 14F
→
12/18 17:32, , 15F
12/18 17:32, 15F
→
12/18 18:28, , 16F
12/18 18:28, 16F
→
12/18 19:32, , 17F
12/18 19:32, 17F
推
12/19 15:33, , 18F
12/19 15:33, 18F
→
12/19 15:34, , 19F
12/19 15:34, 19F
討論串 (同標題文章)
完整討論串 (本文為第 1 之 3 篇)：
理工
8
19