[理工] [電子]-全波整流電路分析
[電路圖]
http://wwwc.moex.gov.tw/examnew1/94/36/311100.pdf
第六題
[市面解法]
(1) is(t)正半週為3.925A ,負半週為 -3.925A
VL(t)為157cos( 377 t)被全波整流
[個人想法]
以下是這題我心目中的疑點:
1.題目中為什麼 (( 電感L 夠大以致其iL(t)電流可視為直流 ))??
VL=L* di(t)/dt ,若iL(t)為直流,則di(t)/dt 為0 => VL=0 ,則短路!
故iL(t)= is(t),那怎麼會是定值?!
2.若電流為直流的話,直接把 L 視為short,C 視為 open ?!?!
3.若(( 輸出漣波電壓為零 )),因為Vr≒Vp * T/2RC ,那C 為無窮大,則C為short
我知道以上充滿了矛盾!整個不曉得怎麼去破解!
想請高手幫我解開這題我的的迷惑 !!
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◆ From: 203.71.156.249
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※ 編輯: pttderek 來自: 203.71.156.249 (11/09 11:41)
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※ 編輯: pttderek 來自: 203.71.156.249 (11/09 13:27)
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