[理工] [微積分]-極限
※ [本文轉錄自 Math 看板]
作者: shareing ( ) 看板: Math
標題: [微積] 極限
時間: Mon Oct 5 18:00:09 2009
Assume that the limit La = lim (a^x-1)/x
x->0
exists and that lim a(x) = 1 for all a > 0
x->0
Prove that Lab = La + Lb for a,b > 0
Hint: (ab)^x - 1 = a^x(b^x-1)+(a^x-1)
做法:
Lab = La + Lb
lim [(ab)^x-1]/x
x->0
= lim a^x(b^x-1)/x+lim (a^x-1)/x
x->0 x->0
= lim (a^x-1)/x + lim (a^x-1)/x
x->0 x->0
我只會做到這邊
請高手指導一下
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