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作者 yandin 在 PTT [ NTPU-CSIE98 ] 看板的留言(推文), 共8則
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92F推:2x4=8 8/7餘數1 所以2的倒數在mod7的條件下是408/03 23:09
96F推:如果a*b=1的話 b就被稱為a的倒數 也就是a的-1次方08/03 23:18
97F→:在mod7的環境裡面 全部的數字被分類成除7餘0~608/03 23:18
98F→:像 {2 9 16 ...} 都算是同一類08/03 23:19
102F→:所以在mod7的環境裡面(也就是0~6的數字) 和2運算會得出108/03 23:21
103F→:的數 就是2的倒數 所以就每個都試試看試出4剛好滿足這樣08/03 23:21
119F推:樓上上上也是808/03 23:42
170F推:代數修兩次就可以看懂了- -08/04 13:11
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