作者查詢 / fkdds
作者 fkdds 在 PTT [ Examination ] 看板的留言(推文), 共36則
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42F推: http://i.imgur.com/p5hgP0Z.jpg 電感電流要連續07/19 08:50
43F→: 電感電流不連續的話 那電感的感應電壓就會變無限大 不合理07/19 08:51
44F→: http://i.imgur.com/55wBb74.jpg07/19 09:01
2F→: 他又沒說有效值 不然你看角度阿07/14 17:35
1F→: diode是理想的嗎?06/25 18:39
1F推: 1的左邊直接往下看就好了06/24 18:27
5F推: 分母因式分解06/24 18:39
6F→: 然後再去湊(提出係數or擴分or約分)出後面的個式子的形式06/24 18:41
13F推: 5和R並聯的跨壓為6R 所以流入並聯區段的電流為6+(6R)/506/04 18:42
14F→: 由柯西荷夫電壓定律 210=20*(6+(6R)/5)+6R 即可求得R=306/04 18:43
1F推: 50.iL(t)=3exp(-1.2)*exp(-0.4(t-1))=3exp(-0.8)*exp(-.4t)05/07 21:36
2F→: I0=iL(1-)=3exp(-1.2t),t=1的值 因電感電流不能突然變化05/07 21:37
3F→: I0=I(1+)05/07 21:38
4F推: 41. V1=60sin(t+30)=>60ㄥ30 I1=3sin(t-30)=>3ㄥ-3005/07 21:47
5F→: P1=Re(0.5*60ㄥ30*3ㄥ30)=90w05/07 21:48
6F→: V2=80sin(3t+60)=>80ㄥ60 I2=4sin(3t+30)=>4ㄥ3005/07 21:49
7F→: P2=Re(0.5*80ㄥ60*4ㄥ-30)=138.56w05/07 21:50
8F→: 不好意思 P1是45W 頻率相同的擺一邊 處理完後再加起來05/07 21:52
11F→: 因為那時t已經是1秒了05/07 22:00
12F→: 41題http://imgur.com/shHoazJ 請忽略前面推文05/07 22:03
15F推: 你解得很好 互相砥礪求進步05/07 22:12
16F推: 然後42題我求的PF=0.758 不知道我的方法對不對就是05/07 22:14
17F→: http://imgur.com/MDQ6MO305/07 22:17
21F推: 感謝解惑!!05/07 23:28
3F推: 平行版電容 C=εA/d05/05 21:54
1F→: (-4,1) (1,2) (2,-4)的電位能加起來就是答案02/06 12:22
14F噓: 請去google01/09 09:06
15F→: 連板規都不爬就直接發文01/09 09:07
1F推: 前兩個一樣08/15 17:42
2F→: 然後應該去爬一下文08/15 17:43