作者查詢 / dryman
作者 dryman 在 PTT [ CSSE ] 看板的留言(推文), 共45則
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6F→:哈,我其實比較熟的FP語言是scrict而不是lazy04/18 08:48
3F推:GJ XDDDDDD07/18 08:29
9F→:現在的架構寫出漢字程式語言不難,但做出來一點意義也沒有07/14 20:30
10F→:因為用漢字來開發遠比英文沒效率多了07/14 20:30
5F推:effective perl 讀過後,很難看懂得都看的懂XD05/24 10:27
14F推:我的心態很單純啊 照題目解出答案而已不是嗎?XD06/03 16:07
1F→:BTW hash值重複時,舊的值會被覆蓋掉,但若是單純判斷有無05/10 08:27
2F→:就沒關係05/10 08:27
3F→:05/10 11:50
4F→:抓出多個idx的版本很醜..不知道Perl有沒有比較好的idx func05/10 11:51
12F→:哪裡要假設輸入資料是什麼請你說清楚05/10 13:06
13F→:演算法之前有推過,這裡再提一次:由yhash找出Y當中符合05/10 13:28
14F→:資格的值,製作yhash及跑過整個x的big-O個別為O(m),O(n)05/10 13:29
15F→:hash的key是arr val, 值的話在本篇是多個idx的集合05/10 13:30
16F→:但存取值因為是O(1),判斷key是否存在也是O(1)05/10 13:31
17F→:故整體的big-O只有O(m)+O(n)05/10 13:32
18F→:05/10 13:32
19F→:之前寫的演算法無法輸出重複的idx,但這不是題目要求的05/10 13:33
20F→:因為題目只有說要找是否存在ij05/10 13:36
25F→:是沒錯啦XD 製作時和存取都不一定是O(1)05/17 17:35
1F→:突然發現原始題目是exist i,j 而不是找全部的解...05/10 00:47
10F→:你真的懂hash是什麼嗎?... = =05/10 01:02
12F→:經由hash function來確認是否有值本來就是O(1)05/10 01:03
14F→:我的key->arr val, value-> arr idx05/10 01:04
16F→:這樣就可以找到idx了啊05/10 01:04
17F→:push @pair, [$xhash{$item},$yhash{$num-$hash}]05/10 01:05
19F→:這不就是用$item及$num-$item當hash key來找arr idx05/10 01:06
20F→:我最後面補充的,是因為原始題目是問i,j是否exists05/10 01:07
21F→:所以可以寫得非常短...印出exist就好05/10 01:07
24F→:噢,我的解法是假設X,Y的值都是unique05/10 01:11
25F→:在個別陣列中不會有重複的值,這我的確沒考慮到05/10 01:11
27F→:不過用hash還是可以解:利用hash做出值不重複的陣列05/10 01:13
28F→:同時記錄每個value的index(用hash of array)05/10 01:13
29F→:做出不重複的陣列後再用本解法得出arr val,用hash of arr05/10 01:14
30F→:反推idx05/10 01:14
31F→:這樣的話就是some small value * O(n)05/10 01:15
32F→:明早還有課,先不戰了XD05/10 01:16
33F→:明天再來PO改版的城市05/10 01:16
1F→:如果是要寫成演算法的話,也是hash key = arr val05/09 23:41
2F→:hash val = key05/09 23:41
3F→:說錯hash val = arr idx05/09 23:42
4F→:製作hash O(n)+O(m), 由x來尋找的話O(n)05/09 23:43
5F→:數組不大的話hash幾乎是O(1)真是太方便了(茶)05/09 23:44
4F推:如果是先給Y做hash呢?05/09 22:12
5F→:然後foreach X[i] , 找Yhash中有沒有想要的值...05/09 22:13
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