[解題] 國2化學 電解質
1.年級:國2
2.科目:理化
3.章節:酸鹼鹽
4.把10g NaCl跟100g CaCl2放再同一杯水中
請問水中正離子個數比負離子個數是幾比幾?
x=10/(23+35.5)是NaCl的莫耳數
y=100/(40+35.5*2)是CaCl2莫耳數
所以正離子比負離子個數是(x+y):(x+2y)
數字很醜....
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