[解題] 國二理化 反應速率
題目是來自一本總複習用的題庫本
範圍是國中理化的反應速率
如下
某一雙氧水製氧的實驗中準備了 A、B、C 三支試管,其內的藥品分別如下
A︰2g 二氧化錳粉末 + 20度C、50mL 1M 的雙氧水
B︰ 40度C、50mL 1M 的雙氧水
C︰2g 二氧化錳粉末 + 20度C、50mL 0.5M 的雙氧水
問以上三試管之反應速率快慢順序為何?
題庫給的解答是 B > A > C
我可以理解 C 一定擺在最後
但是 A 跟 B 的順序該如何決定呢?
A 是有催化劑但溫度較低, B 是沒催化劑但溫度較高
想請教板上前輩這題目如果只用國中理化教的東西有辦法做答嗎? @@
我在想這題大概會動用到高中的東西......= =a
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