求極值
王博書上的題目
設
x 3 -π 3π
f(X)=∫ (x-t)cos t dt , ── < x < ── 求極值
0 2 2
' x 3
他的過程中寫 f (x)=∫ cos t dt 這邊我看不懂他是怎來的
0
有人知道怎來的嗎
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 118.160.70.84
→
04/11 00:44, , 1F
04/11 00:44, 1F
→
04/11 00:46, , 2F
04/11 00:46, 2F
推
04/11 00:48, , 3F
04/11 00:48, 3F
→
04/11 00:49, , 4F
04/11 00:49, 4F
→
04/11 00:50, , 5F
04/11 00:50, 5F
→
04/11 00:50, , 6F
04/11 00:50, 6F
推
04/11 01:21, , 7F
04/11 01:21, 7F
→
04/11 12:13, , 8F
04/11 12:13, 8F
→
04/11 12:14, , 9F
04/11 12:14, 9F
→
04/11 16:47, , 10F
04/11 16:47, 10F
討論串 (同標題文章)