Re: [考古] 請教兩題有理化的算法
※ 引述《a82114p (lun)》之銘言：
: 2的立方根 減 1
: 2. ----------------------- = ?
: 7
= (2^(1/3) - 1 ) * ( 2^(2/3) + 2 ^ (1/3) + 1 )
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7 * (2^(2/3) + 2 ^ (1/3) + 1 )
= (2^(1/3))^3 - 1^3
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7 * (2^(2/3) + 2 ^ (1/3) + 1)
= 2 - 1
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7 * (2^(2/3) + 2 ^ (1/3) + 1 )
= 1
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7 * (2^(2/3) + 2 ^ (1/3) + 1 )
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3% exceeds 2% by 50% , and not 1%.
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09/24 20:16, , 1F
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