[考古] 中興應數96
show that
x 2x[(1-x^2)^(1/2)]
2 ∫ (1-t^2)^(-1/2) dt = ∫ (1-t^2)^(-1/2) dt .
0 0
我用右式 算出來的結果是 -2 / √(1-x^2)
左式 則是 2 / √(1-x^2)
請問是計算部份出錯嗎 ?
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