[考古] 利用馬克勞林求極限
tan(sinx)-sin(tanx)
lim ----------- = A
x→0 x^α
Ans:α=7 A=149/1680
tan(sinx) = x + (1/6)x^3 + (-1/40)x^5 + (-3/560)x^7 +.......
^^^^^^^ ^^^^^^^
sin(tanx) = x + (1/6)x^3 + (-1/40)x^5 + (-79/840)x^7 +......
^^^^^^^ ^^^^^^^^
小弟不知道為什麼^^^^^是這樣的係數
算了好久= =
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