Re: [積分] 求面積和一題極限

看板trans_math作者 (弧形)時間16年前 (2010/02/06 00:56), 編輯推噓0(000)
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※ 引述《BIEGABOY (BIEGABOY)》之銘言: : 1.Find the area of the region bounded by the curve x=tcost,y=tsint, : 0<=t<=pi ,and the x-axis. 畫成極座標︰r=θ π 1 2 3 所求=∫ ---r dθ=π /6 0 2 : 2.lim [ (x^98+2009x^97+1)^1/98-x ] : x->無限大 -1 -98 -1 -98 1/98 1/98 x(2009x +x ) 原式=lim x[(1+2009x +x ) - 1 ]=lim --------------------------------- x→∞ x→∞ (1+2009x^-1 +x^-98)^97/98 +...+1 n n n-1 n-2 n-1 =2009/98 ,其中a -b =(a-b)(a +a b+...+b ) -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 59.121.2.38
文章代碼(AID): #1BR4tHeh (trans_math)
文章代碼(AID): #1BR4tHeh (trans_math)