Re: [積分] 台聯大考古
Suppose x = √2 u - √(2/3) v
y = √2 u + √(2/3) v
|J| = 4/√3
And
2 2 2 2
x + xy + y = 2 (u + v ) = 1
Area = ∫∫dA = ∫∫ dxdy = ∫∫|J|dudv = 4/√3 ∫∫du dv
2π 1/√2
= 4/√3 ∫ ∫ r dr dθ
0 0
= 2π/√3
應該是這樣吧= =?
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