Re: [微分] 偏微分
※ 引述《home1265 (saber)》之銘言：
: 如果變數x,y,z之間有函數關係f(x,y,z)=0,
: f為可導且導函數為連續,
: 則 證明:
: δy| δz| δx|
: —| * —| * －| =-1
: δx|z δy|x δz|y
: 拜託各位大大幫我解答了><
: PS.抱歉打得這麼不清楚....囧>
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1.f(x,y(x,z),z)=0
df
── = f_x + f_y．y_x =0
dx
f_x
=> y_x = - ───
f_y
2.f(x,y,z(x,y))=0
df
── = f_y + f_z．z_y =0
dy
f_y
=> z_y = - ───
f_z
3.f(x(y,z),y,z)=0
df
── = f_x．x_z + f_z =0
dz
f_z
=> x_z = - ───
f_x
4.
y_x．z_y．x_z = -1
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