Re: [積分] 95成大插大第9題
※ 引述《yuchda (ssd)》之銘言:
: Find the area of the region Ω bounded by the curves
: x^2-4xy+4y^2-2x-y-1=0 and y=2/5.
: 要怎麼做啊
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x^2 -4xy+4 y^2 -2x-y-1=0
-> (x-2y)^2 -(2x+y+1)=0
Set u=x-2y,v=2x+y+1
1.先求 u,v座標下的面積
x^2 -4xy+4 y^2 -2x-y-1=0
-> v = u^2
y=2/5
->v=2u+3
由圖得知其交點為 (-1,1),(3,9)
3
Area = ∫ {(2u+3)- u^2}du = 32/3
-1
2.由 Jacobian 求在x,y座標下的面積
∵u=x-2y,v=2x+y+1
∴x=(0.2)u+(0.4)v-0.4,y=(-0.4)u+(0.2)v-0.2
┌ dx ┐ ┌ 0.2 0.4 ┐┌ du ┐
│ │= │ ││ │
└ dy ┘ └ -0.4 0.2 ┘└ dv ┘
∴ |J| = 1/5
32 1 32
所求 = ── .── = ──
3 5 15
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