Re: [積分] 84清華
※ 引述《gghh711 (lara)》之銘言:
: ∫ln[x+√ (1+x^2)]dx=?
2x
1 + ----------
2√(1+x^2)
= x( ln(x+√(1+x^2)) ) - ∫ x ---------------- dx
x + √(1+x^2)
x
= x( ln(x+√(1+x^2)) ) - ∫---------- dx
√(1+x^2)
= x( ln(x+√(1+x^2)) ) - √(1+x^2) + C
--
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6年前
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