Re: [考古] 88台大c的證明題

看板trans_math作者 ( )時間17年前 (2008/07/09 09:18), 編輯推噓0(000)
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※ 引述《vivaonly (viva)》之銘言: : 計算題乙 (2/pi)x〈 sinx 〈x , 當 0〈 x〈 (pi/2) : 這題要怎麼證明呢?? : 請大大指教 謝謝!!!! sinx π ------ , 0 < x ≦ --- x 2 令 f(x) = 1 , x = 0 sinx lim f(x) = lim ------ = 1 = f(0) => f(x) 在 x = 0 連續 x→0+ x→0+ x π 所以 f(x) 在 [0 , ---] 上連續 2 π Claim: x < tanx if 0 < x < --- 2 π pf: 令 g(x) = tanx - x , 0 ≦ x ≦ --- 2 π 則 g'(x) = (secx)^2 - 1 > 0 , for all 0 < x < --- 2 π 當 0 < x < --- 時 , 由均值定理得 2 g(x) - g(0) = (g'(c))(x - 0) , 0 < c < x 因為 g(0) = 0 , 且 g'(c) > 0 , x > 0 π 所以 g(x) = (g'(c))(x) > 0 , for all 0 < x < --- 2 π tanx - x > 0 , for all 0 < x < --- 2 π x < tanx , for all 0 < x < --- 2 (x)(cosx) - sinx 因為 f'(x) = ---------------- x^2 (cosx)(x - tanx) π = ---------------- < 0 , for all 0 < x < --- x^2 2 π => f(x) 在 [0 , ---] 上為嚴格遞減函數 2 2 π π => --- = f(---) < f(x) < f(0) = 1 , for all 0 < x < --- π 2 2 2 sinx π => --- < ---- < 1 , for all 0 < x < --- π x 2 2 π => (---)(x) < sinx < x , for all 0 < x < --- π 2 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 61.66.173.21
文章代碼(AID): #18T17hMH (trans_math)
文章代碼(AID): #18T17hMH (trans_math)