Re: [考古] 94政大金融
※ 引述《ggyy340 (阿甘)》之銘言：
: Given y=[tan(x+y)]^2 ,use implicit differentiation to find
: dy
: --- in terms of variable y only
: dx
: 不會算 請高手幫忙 謝謝
y = [tan(x+y)]^2
等號兩邊對 x 微分
dy dy
---- = (((sec(x+y))^2)(1 + ----)
dx dx
dy
(1 - (sec(x+y))^2)(----) = ((sec(x+y))^2
dx
dy ((sec(x+y))^2
---- = -------------------
dx 1 - (sec(x+y))^2
--
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