Re: [微分] 94政大資管

看板trans_math作者 (^______^)時間18年前 (2007/10/24 13:30), 編輯推噓1(100)
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※ 引述《bitchdog (PEaCE)》之銘言: : Let f(x)={ √¯¯¯ : (x+4) -3 : ------------ , x≠5 : x-5 : {f(5)=c : and let f be continuous at x=5 then c=? √(x+4) - 3 ------------- , x≠5 x - 5 f(x) = f(5) = c f(x) is continuous => lim f(x) = f(5) = c x→5 √(x+4) - 3 lim ------------- x→5 x - 5 (√(x+4) - 3)(√(x+4) + 3) = lim ---------------------------- x→5 (x-5)(√(x+4) + 3) x + 4 - 9 = lim -------------------- x→5 (x-5)(√(x+4) + 3) x - 5 = lim -------------------- x→5 (x-5)(√(x+4) + 3) 1 = lim -------------- x→5 √(x+4) + 3 1 = ------------- √(5+4) + 3 1 1 1 = ---------- = ------- = --- √9 + 3 3 + 3  6 1 所以 c = --- 6 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.119.66.26

10/24 20:45, , 1F
這題後來有想出來,謝謝
10/24 20:45, 1F
文章代碼(AID): #177jXzOc (trans_math)
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文章代碼(AID): #177jXzOc (trans_math)