Re: 台大數假ㄧ題證明
※ 引述《HUJIKOLP (UUOJKLJLKJK)》之銘言:
: Let f be continuous on a rectangular region (a,b)X(c,d)
: prove that the function F defined by
: F(X)=Sf(x,y)dy 積c~d x屬於(a,b)is continuous on(a,b)
有錯請指正囉~~
d
F(x)=∫ f(x,y)dy
c
d
F(x+h)=∫ f(x+h,y)dy
c
d d
lim F(x+h)-F(x) = lim [(∫ f(x+h,y)dy) -(∫ f(x,y)dy)]
h→0 h→0 c c
d
=lim ∫[f(x+h,y)-f(x,y)]dy fix x, and let f(x+h,y)-f(x,y)=G(y)
h→0 c
d
=lim ∫ G(y)dy
h→0 c
(let P={c=a1,a2,....an=d} is a partition of [c,d] Max|P|→0 as n→∞)
1
=lim lim --- ΣG(ai)
h→0 n→0 n
1
=lim --- Σ lim G(ai)
n→0 n h→0
d
= ∫ {lim [f(x+h,y)-f(x,y)]} dy
c h→0
-----------------------
這項因為f在(a,b)X(c,d)連續故為0
=0
lim F(x+h) = F(x)
h→0
: =≒≠≡≡<>≦≧
: ∴∵∫∮∩∪㏑㏒√→∞∠△°
: ⅠⅡⅢⅣⅤⅥⅦⅧⅨⅩ
: ΑΒΓΔΕΖΗΘΙΚΛΜΝΞΟΠΡΣΤΥΦΧΨΩ
: αβγδεζηθικλμνξοπρστυφχψω
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 125.226.173.220
※ 編輯: pobm 來自: 125.226.173.220 (06/16 12:22)
推
06/16 12:28, , 1F
06/16 12:28, 1F
→
06/16 15:26, , 2F
06/16 15:26, 2F
推
06/16 16:33, , 3F
06/16 16:33, 3F
推
06/16 17:21, , 4F
06/16 17:21, 4F
※ 編輯: pobm 來自: 125.226.59.121 (06/16 17:33)
推
06/16 17:33, , 5F
06/16 17:33, 5F
→
06/16 17:34, , 6F
06/16 17:34, 6F
→
06/16 17:34, , 7F
06/16 17:34, 7F
→
06/16 17:35, , 8F
06/16 17:35, 8F
推
06/16 17:37, , 9F
06/16 17:37, 9F
→
06/16 17:37, , 10F
06/16 17:37, 10F
→
06/16 17:38, , 11F
06/16 17:38, 11F
→
06/16 17:39, , 12F
06/16 17:39, 12F
→
06/16 17:42, , 13F
06/16 17:42, 13F
推
06/16 17:43, , 14F
06/16 17:43, 14F
→
06/16 17:46, , 15F
06/16 17:46, 15F
推
06/16 17:51, , 16F
06/16 17:51, 16F
推
06/16 17:54, , 17F
06/16 17:54, 17F
推
06/16 17:56, , 18F
06/16 17:56, 18F
→
06/16 17:59, , 19F
06/16 17:59, 19F
→
06/16 18:00, , 20F
06/16 18:00, 20F
→
06/16 18:02, , 21F
06/16 18:02, 21F
→
06/16 18:02, , 22F
06/16 18:02, 22F
→
06/16 18:03, , 23F
06/16 18:03, 23F
→
06/16 18:04, , 24F
06/16 18:04, 24F
→
06/16 18:04, , 25F
06/16 18:04, 25F
→
06/16 18:05, , 26F
06/16 18:05, 26F
→
06/16 18:06, , 27F
06/16 18:06, 27F
推
06/16 23:13, , 28F
06/16 23:13, 28F
→
06/16 23:14, , 29F
06/16 23:14, 29F