Re: [積分] 怎解
※ 引述《SeaBear ( 來亂的 )》之銘言：
: (dy/dt)+(y^2)=sint
: 怎解
: 查過題目沒錯
let sint=x
then d(sint)=dx
we have 1/dt=cost/dx=(1-x^2)^(1/2)/dx
take 1/dt=cost/dx=(1-x^2)^(1/2)dx to the equation
then we have (dy/dx)=x/(1-x^2)^(1/2)-(y^2)/(1-x^2)^(1/2)
it's a Riccati equation
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