Re: [積分] 問一題積分∫x^0.5*e^x^0.5

看板trans_math作者 (^______^)時間19年前 (2006/05/17 11:24), 編輯推噓0(000)
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※ 引述《otuse (pumacat)》之銘言: : 請問要怎麼解阿~"~ √x ∫(√x)*(e ) dx 令 t = √x , 則 x = t^2 => dx = 2t dt √x ∫(√x)*(e ) dx t = ∫(t)*(e )*(2t) dt 2 t = (2)*(∫(t )*(e ) dt) 2 t t = (2)*((t )*(e ) - ∫(e )*(2t) dt) 2 t t = (2)*((t )*(e ) - (2)*(∫(t)*(e ) dt) 2 t t t = (2)*((t )*(e ) - (2)*((t)*(e ) - ∫e dt)) 2 t t t = (2)*((t )*(e ) - (2)*((t)*(e ) - e )) + c 2 t t t = (2)*(t )*(e ) - (4)*(t)*(e ) + (4)*(e ) + c √x √x √x = (2)*(x)*(e ) - (4)*(√x)*(e ) + (4)*(e ) + c -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.119.27.52
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文章代碼(AID): #14QfU6r8 (trans_math)