[問題] 1+2+3+4+.....=?
1+2+3+4+5+6+........一直加到無限大,答案會是多少?
任何人直覺應該都是....無限大吧?但我說答案是-1/12!!
你一定說我瞎掰胡扯,讓我證明給你看吧!
首先先證明
S1 = 1 - 1 + 1 -1 + 1 - 1 ..... = 1/2
這很容易 S1+S1 =(1 -1 +1 -1 .......) +
(1 -1 +1 .......) <-故意錯開
=1 +0 +0 +0 +0..... 上下相加
=1
所以 2*S1 = 1 => S1 = 1/2
接著我們計算S2 = 1-2+3-4+5-6+7-8.......=?
同樣有 S2+S2 = (1-2+3-4+5-6+7-8....)+
( 1-2+3-4+5-6+7....)
= 1-1+1-1+1.......
= S1
因此 S2 = S1/2 = 1/4
最後我們計算S3 = 1+2+3+4+5+6+7+8+9.....
令 S3-S2 = (1+2+3+4+5+6+7+8+.........)
-(1-2+3-4+5-6+7-8+.........) 同樣還是做上下相減
= 0+4+0+8+0+12+0+.........
= 4*(1+2+3+4+5+........)
= 4*S3
簡單移項得到 3*S3 = -S2 = -1/4
=> S3 = -1/12!!!!!!!!!!!!!!!!!!!!!!!!
這太恐怖了吧!?!?
拿去給你數學老師看,相信他們也會被你嚇傻,整個證明過程看起來都沒有錯誤~
結果卻是荒謬至極,問題到底在那呢?
請大家好好想想吧! (開燈後有我的見解)
S1 = 1/2 本身就是很大問題!1-1+1-1 .... 得到的值是震盪的!
以數學角度來說根本就是無法計算、未定義的數
當我們移位相加時候,在最無窮項永遠會有個值讓答案仍然是震盪的~
而我們在此故意忽略,於是得到一個破天荒的結論..........
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